3(x+1)^2/3=48

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Solution for 3(x+1)^2/3=48 equation: 


x in (-oo:+oo)

(3*(x+1)^2)/3 = 48 // - 48

(3*(x+1)^2)/3-48 = 0

(x+1)^2-48 = 0

(x+1)^2-48 = 0

x^2+2*x-47 = 0

x^2+2*x-47 = 0

x^2+2*x-47 = 0

DELTA = 2^2-(-47*1*4)

DELTA = 192

DELTA > 0

x = (192^(1/2)-2)/(1*2) or x = (-192^(1/2)-2)/(1*2)

x = (8*3^(1/2)-2)/2 or x = (-8*3^(1/2)-2)/2

(x-((-8*3^(1/2)-2)/2))*(x-((8*3^(1/2)-2)/2)) = 0

(x-((-8*3^(1/2)-2)/2))*(x-((8*3^(1/2)-2)/2)) = 0

( x-((-8*3^(1/2)-2)/2) )

x-((-8*3^(1/2)-2)/2) = 0 // + (-8*3^(1/2)-2)/2

x = (-8*3^(1/2)-2)/2

( x-((8*3^(1/2)-2)/2) )

x-((8*3^(1/2)-2)/2) = 0 // + (8*3^(1/2)-2)/2

x = (8*3^(1/2)-2)/2

x in { (-8*3^(1/2)-2)/2, (8*3^(1/2)-2)/2 }

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